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Check Armstrong

You are given an integer 'n'.

Return 'true' if 'n' is an Armstrong number, and 'false' otherwise.


An Armstrong number is a number (with 'k' digits) such that the sum of its digits raised to 'kth' power is equal to the number itself. 
For example, 371 is an Armstrong number because 3^3 + 7^3 + 1^3 = 371.

bool checkArmstrong(int n){
    //Write your code here
    int num=0,temp;
    int count=0;
    for(int i=n;i>0;i=i/10)
     count++;
    for(int i=n;i>0;i=i/10)
    {
        temp=i%10;
        num=num+pow(temp,count);
    }
   if(num==n)
    return true;
   else
    return false;
}

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